3/x^2-7x+6+1/x^2-1=x+3/x^2-5x-6

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Solution for 3/x^2-7x+6+1/x^2-1=x+3/x^2-5x-6 equation: 



3/x^2-7x+6+1/x^2-1=x+3/x^2-5x-6

We move all terms to the left:

3/x^2-7x+6+1/x^2-1-(x+3/x^2-5x-6)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2-5x-6)!=0

x∈R



We add all the numbers together, and all the variables

-7x+3/x^2+1/x^2-(x+3/x^2-5x-6)+5=0

We get rid of parentheses

-7x+3/x^2+1/x^2-x-3/x^2+5x+6+5=0

We multiply all the terms by the denominator


-7x*x^2-x*x^2+5x*x^2+6*x^2+5*x^2+3+1-3=0

We add all the numbers together, and all the variables

11x^2-7x*x^2-x*x^2+5x*x^2+1=0

Wy multiply elements

11x^2-7x^3-1x^3+5x^3+1=0

We do not support expression: x^3

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